12t^2-30=0

Solution for 12t^2-30=0 equation:

12t^2-30=0

a = 12; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·12·(-30)
Δ = 1440
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1440}=\sqrt{144*10}=\sqrt{144}*\sqrt{10}=12\sqrt{10}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{10}}{2*12}=\frac{0-12\sqrt{10}}{24}
=-\frac{12\sqrt{10}}{24}
=-\frac{\sqrt{10}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{10}}{2*12}=\frac{0+12\sqrt{10}}{24}
=\frac{12\sqrt{10}}{24}
=\frac{\sqrt{10}}{2}
$